GuruMCQs.com provides all updated Mathematics Multiple Choice Questions (MCQs). Most repeated Math MCQs section, frequently encountered in Inspector, ASI, Sub-inspector, Constable, FPSC, PPSC, ETEA, FIA, Police, Army, Navy, Airforce, IB, MOFA, ASF, LHC, Educators, and various other competitive exams, as well as government and private job assessments. Mathematics most repeated MCQs include Basic Math MCQs, Algebra MCQs, Quantitative MCQs with Solutions, Basic Arithmetic MCQs, Geometry MCQs, Ratio and Proportion MCQs, Probability MCQs, Percentage MCQs, Average, Percentage, Problem on Ages MCQs, Time and Distance MCQs, HCF and LCM MCQs, Logarithms MCQs, Discount MCQs, Interestmcqs, Decimal Fraction MCQs …and other  Also, check MCQs on Accountinghere.

511. Find the roots of quadratic equation: 3×2 – 7x – 6 = 0?
A. -6, 3
B. 3, -2/3
C. -5, 2
D. -9, 2

Explanation
3×2 – 9x + 2x – 6 = 0
3x(x – 3) + 2(x – 3) = 0
(x – 3)(3x + 2) = 0 => x = 3, -2/3

512. Find the roots of quadratic equation: x2 + x – 42 = 0?
A. -6, 7
B. -8, 7
C. 14, -3
D. -7, 6

Explanation:
x2 + 7x – 6x + 42 = 0
x(x + 7) – 6(x + 7) = 0
(x + 7)(x – 6) = 0 => x = -7, 6

513. Find the roots of quadratic equation: 2×2 + 5x + 2 = 0?
A. -2, -1/2
B. 4, -1
C. 4, 1
D. -2, 5/2

Explanation:
2×2 + 4x + x + 2 = 0
2x(x + 2) + 1(x + 2) = 0
(x + 2)(2x + 1) = 0 => x = -2, -1/2

514. I. a2 – 13a + 42 = 0,
II. b2 – 15b + 56 = 0 to solve both the equations to find the values of a and b?
A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b.

Explanation:
I. a2 – 13a + 42 = 0
=>(a – 6)(a – 7) = 0 => a = 6, 7
II. b2 – 15b + 56 = 0
=>(b – 7)(b – 8) = 0 => b = 7, 8
=>a ≤ b

515. I. a3 – 988 = 343,
II. b2 – 72 = 49 to solve both the equations to find the values of a and b?
A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b

Explanation:
a3 = 1331 => a = 11
b2 = 121 => b = ± 11
a ≥ b

516. I. 9a2 + 18a + 5 = 0,
II. 2b2 + 13b + 20 = 0 to solve both the equations to find the values of a and b?
A. If a > b
B. If a ≥ b
C. If a < b
D. If a ≤ b

Explanation:
I. 9a2 + 3a + 15a + 5 = 0
=>(3a + 5)(3a + 1) = 0 => a = -5/3, -1/3
II. 2b2 + 8b + 5b + 20 = 0
=>(2b + 5)(b + 4) = 0 => b = -5/2, -4
a is always more than b.
a > b.

517. I. x2 + 11x + 30 = 0,
II. y2 + 15y + 56 = 0 to solve both the equations to find the values of x and y?
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y

518. I. x2 + 3x – 18 = 0,
II. y2 + y – 30 = 0 to solve both the equations to find the values of x and y?
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established.

Explanation:
I. x2 + 6x – 3x – 18 = 0
=>(x + 6)(x – 3) = 0 => x = -6, 3
II. y2 + 6y – 5y – 30 = 0
=>(y + 6)(y – 5) = 0 => y = -6, 5

519. I. x2 + 9x + 20 = 0,
II. y2 + 5y + 6 = 0 to solve both the equations to find the values of x and y?
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y

Explanation
I. x2 + 4x + 5x + 20 = 0
=>(x + 4)(x + 5) = 0 => x = -4, -5
II. y2 + 3y + 2y + 6 = 0
=>(y + 3)(y + 2) = 0 => y = -3, -2
= x <

520. I. x2 – x – 42 = 0,
II. y2 – 17y + 72 = 0 to solve both the equations to find the values of x and y?
A. If x < y
B. If x > y
C. If x ≤ y
D. If x ≥ y
E. If x = y or the relationship between x and y cannot be established.

Explanation:
I. x2 – 7x + 6x – 42 = 0
=> (x – 7)(x + 6) = 0 => x = 7, -6
II. y2 – 8y – 9y + 72 = 0
=> (y – 8)(y – 9) = 0 => y = 8, 9
=> x < y